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Codility 24번 MaxProfit 본문

개발/알고리즘

Codility 24번 MaxProfit

룬아님 2019. 9. 15. 15:13

MaxProfit

 

An array A consisting of N integers is given. It contains daily prices of a stock share for a period of N consecutive days. If a single share was bought on day P and sold on day Q, where 0 ≤ P ≤ Q < N, then the profit of such transaction is equal to A[Q] − A[P], provided that A[Q] ≥ A[P]. Otherwise, the transaction brings loss of A[P] − A[Q].

For example, consider the following array A consisting of six elements such that:

A[0] = 23171 A[1] = 21011 A[2] = 21123 A[3] = 21366 A[4] = 21013 A[5] = 21367

If a share was bought on day 0 and sold on day 2, a loss of 2048 would occur because A[2] − A[0] = 21123 − 23171 = −2048. If a share was bought on day 4 and sold on day 5, a profit of 354 would occur because A[5] − A[4] = 21367 − 21013 = 354. Maximum possible profit was 356. It would occur if a share was bought on day 1 and sold on day 5.

Write a function,

class Solution { public int solution(int[] A); }

that, given an array A consisting of N integers containing daily prices of a stock share for a period of N consecutive days, returns the maximum possible profit from one transaction during this period. The function should return 0 if it was impossible to gain any profit.

For example, given array A consisting of six elements such that:

A[0] = 23171 A[1] = 21011 A[2] = 21123 A[3] = 21366 A[4] = 21013 A[5] = 21367

the function should return 356, as explained above.

Write an efficient algorithm for the following assumptions:

  • N is an integer within the range [0..400,000];
  • each element of array A is an integer within the range [0..200,000].

    Copyright 2009–2019 by Codility Limited. All Rights Reserved. Unauthorized copying, publication or disclosure prohibited.

 

class Solution {
    public int solution(int[] A) {
        if(A.length < 2) {
            return 0;
        }

        int max = A[1];
        int min = A[0];
        int benefit = A[1] - A[0];
        
        for (int i = 0; i < A.length; i++) {
            if(A[i] < min) {
                min = A[i];
            } else {
                benefit = Math.max(benefit, A[i] - min);
            }
        }

        return benefit;
    }
}

https://app.codility.com/demo/results/trainingZN8XQK-N7J/

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